X^2+3x+2=(x+2)

Solution for X^2+3x+2=(x+2) equation:

X^2+3X+2=(X+2)

We move all terms to the left:

X^2+3X+2-((X+2))=0


We calculate terms in parentheses: -((X+2)), so:

(X+2)

We get rid of parentheses

X+2

Back to the equation:

-(X+2)


We get rid of parentheses

X^2+3X-X-2+2=0

We add all the numbers together, and all the variables

X^2+2X=0

a = 1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*1}=\frac{-4}{2}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*1}=\frac{0}{2}
=0
$